JEE Mains · Maths · STD 12 - 8. Application and integration
If the area bounded by the curve \(2 y^2=3 x\), lines \(x+y=3, y=0\) and outside the circle \((x-3)^2+y^2=2\) is \(A\), then \(4(\pi+4 A )\) is equal to \(.........\).
- A \(42\)
- B \(41\)
- C \(43\)
- D \(44\)
Answer & Solution
Correct Answer
(A) \(42\)
Step-by-step Solution
Detailed explanation
\(y^2=\frac{3 x}{2}, x+y=3, y=0\) \(2 y^2=3(3-y)\) \(2 y^2+3 y-9=0\) \(2 y^2-3 y+6 y-9=0\) \((2 y-3)(y+2)=0 ; y=3 / 2\) \(\text { Area }\left[\int_0^{\frac{3}{2}}\left(x_R-x_2\right) d y\right)-A_1\)…
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