JEE Mains · Maths · STD 11 - 10.1 circle and system of circle
If \(P (6,1)\) be the orthocentre of the triangle whose vertices are \(A (5,-2), B (8,3)\) and \(C ( h , k )\), then the point \(C\) lies on the circle:
- A \(x^2+y^2-61=0\)
- B \(x^2+y^2-52=0\)
- C \(x^2+y^2-65=0\)
- D \(x^2+y^2-74=0\)
Answer & Solution
Correct Answer
(C) \(x^2+y^2-65=0\)
Step-by-step Solution
Detailed explanation
Slope of \(AD =3\) Slope of \(BC =-\frac{1}{3}\) equation of \(BC =3 y + x -17=0\) Slope of \(BE =1\) Slope of \(AC =-1\) Equation of AC is \(x + y - 3 = 0\)
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