JEE Mains · Maths · STD 11 - 10.1 circle and system of circle
For the four circles \(M , N , O\) and \(P ,\) following four equations are given Circle \(M : x ^{2}+ y ^{2}=1\) ; Circle \(N : x ^{2}+ y ^{2}-2 x =0\) ; Circle \(O : x ^{2}+ y ^{2}-2 x -2 y +1=0\) ;Circle \(P: x^{2}+y^{2}-2 y=0\) If the centre of circle \(M\) is joined with centre of the circle \(N\), further centre of circle \(N\) is joined with centre of the circle \(O ,\) centre of circle \(O\) is joined with the centre of circle \(P\) and lastly, centre of circle \(P\) is joined with centre of circle \(M ,\) then these lines form the sides of a
- A Rhombus
- B Square
- C Rectangle
- D Parallelogram
Answer & Solution
Correct Answer
(B) Square
Step-by-step Solution
Detailed explanation
\(M: x^{2}+y^{2}=1\) \((0,0)\) \(N: x^{2}+y^{2}-2 x=0\) \((1,0)\) \(O : x ^{2}+ y ^{2}-2 x -2 y +1=0\) \((1,1)\) \(P: x^{2}+y^{2}-2 y=0\) \((0,1)\)
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