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JEE Mains · Maths · STD 11 - 7. binomial theoram

For a positive integer \(n,\left(1+\frac{1}{x}\right)^{n}\) is expanded in increasing powers of \(x\). If three consecutive coefficients in this expansion are in the ratio, \(2: 5: 12,\) then \(n\) is equal to

  1. A \(115\)
  2. B \(128\)
  3. C \(138\)
  4. D \(118\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(118\)

Step-by-step Solution

Detailed explanation

\({ }^{ n } C _{ r -1}:{ }^{ n } C _{ r }:{ }^{ n } C _{ r +1}=2: 5: 12\) Now \(\frac{{ }^{n} C_{r-1}}{{ }^{n} C_{r}}=\frac{2}{5}\) \(\Rightarrow 7 r=2 n+2\) \(\frac{{ }^{n} C_{r}}{{ }^{n} C_{r+1}}=\frac{5}{12}\) \(\Rightarrow 17 r =5 n -12\) On solving (1)\(\&(2)\)…
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