JEE Mains · Maths · STD 11 - 8. sequence and series
For \(0<\mathrm{c}<\mathrm{b}<\mathrm{a}\), let \((\mathrm{a}+\mathrm{b}-2 \mathrm{c}) \mathrm{x}^2+(\mathrm{b}+\mathrm{c}-2 \mathrm{a}) \mathrm{x}\) \(+(c+a-2 b)=0\) and \(\alpha \neq 1\) be one of its root. Then, among the two statements \((I)\) If \(\alpha \in(-1,0)\), then \(\mathrm{b}\) cannot be the geometric mean of \(\mathrm{a}\) and \(\mathrm{c}\) \((II)\) If \(\alpha \in(0,1)\), then \(\mathrm{b}\) may be the geometric mean of \(a\) and \(c\)
- A Both \((I)\) and \((II) \)are true
- B Neither \((I)\) nor \((II)\) is true
- C Only \((II)\) is true
- D Only \((I)\) is true
Answer & Solution
Correct Answer
(A) Both \((I)\) and \((II) \)are true
Step-by-step Solution
Detailed explanation
\(\mathrm{f}(\mathrm{x})=(\mathrm{a}+\mathrm{b}-2 \mathrm{c}) \mathrm{x}^2+(\mathrm{b}+\mathrm{c}-2 \mathrm{a}) \mathrm{x}+(\mathrm{c}+\mathrm{a}-2 \mathrm{~b}) \)…
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