JEE Mains · Maths · STD 11 - 10.1 circle and system of circle
Choose the correct statement about two circles whose equations are given below \(x^{2}+y^{2}-10 x-10 y+41=0\) \(x^{2}+y^{2}-22 x-10 y+137=0\)
- A circles have same centre
- B circles have no meeting point
- C circles have only one meeting point
- D circles have two meeting points
Answer & Solution
Correct Answer
(C) circles have only one meeting point
Step-by-step Solution
Detailed explanation
\(x^{2}+y^{2}-10 x-10 y+41=0\) \(A (5,5), R _{1}=3\) \(x^{2}+y^{2}-22 x-10 y+137=0\) \(B (11,5), R _{2}=3\) \(AB =6= R _{1}+ R _{2}\) Touch each other externally \(\Rightarrow\) circles have only one meeting point.
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