JEE Mains · Maths · STD 12 - 10. vector algebra
Let the position vectors of the points \(A , B , C\) and \(D\) be \(5 \hat{i}+5 \hat{j}+2 \lambda \hat{k}, \hat{i}+2 \hat{j}+3 \hat{k},-2 \hat{i}+\lambda \hat{j}+4 \hat{k}\) and \(-\hat{ i }+5 \hat{ j }+6 \hat{ k }\). Let the set \(S =\{\lambda \in R\) : The points \(A\), \(B , C\) and D are coplanar \(\}\). Then \(\sum_{\lambda \in S}(\lambda+2)^2\) is equal to
- A \(41\)
- B \(25\)
- C \(13\)
- D \(\frac{37}{2}\)
Answer & Solution
Correct Answer
(A) \(41\)
Step-by-step Solution
Detailed explanation
Since \(A, B, C, D\) are coplanner Hence \(\left[\begin{array}{lll}\overrightarrow{ BA } & \overrightarrow{ CA } & \overrightarrow{ DA }\end{array}\right]=0\)…
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