JEE Mains · Maths · STD 12 - 13. probability
Bag \(A\) contains \(2\) white, \(1\) black and \(3\) red balls and bag \(B\) contains \(3\) black, \(2\) red and \(n\) white balls. One bag is chosen at random and \(2\) balls drawn from it at random, are found to be \(1\) red and \(1\) black. If the probability that both balls come from Bag \(A\) is \(\frac{6}{11}\), then \(n\) is equal to
- A \(13\)
- B \(6\)
- C \(4\)
- D \(3\)
Answer & Solution
Correct Answer
(C) \(4\)
Step-by-step Solution
Detailed explanation
\(E _{1}=\text { denotes selection for } 1^{\text {st }} \text { bag }\) \(E _{2}=\text { denotes selection for } 2^{\text {nd }} \text { bag }\) \(P \left( E _{1}\right)=\frac{1}{2}, P \left( E _{2}\right)=\frac{1}{2}\) \(A =\) selected balls are \(1\) red and \(1\) black…
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