JEE Mains · Maths · STD 11 - 6. permutation and combination
A person has three different bags and four different books. The number of ways, in which he can put these books in the bags so that no bag is empty, is:
- A \(18\)
- B \(36\)
- C \(39\)
- D \(72\)
Answer & Solution
Correct Answer
(B) \(36\)
Step-by-step Solution
Detailed explanation
To ensure no bag is empty, exactly one bag must contain 2 books and the other two bags must contain 1 book each. The number of ways to choose 2 books out of 4 to be kept together is \(^{4}C_{2} = 6\) Now, we have 3 units (one pair of books and two single books) to be distributed…
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