JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
A student needs to prepare a buffer solution of propanoic acid and its sodium salt with \(pH\) \(4.\) The ratio of \(\frac{\left[ CH _{3} CH _{2} COO ^{-}\right]}{\left[ CH _{3} CH _{2} COOH \right]}\) required to make buffer is ..... Given : \(K _{ a }\left( CH _{3} CH _{2} COOH \right)=1.3 \times 10^{-5}\)
- A \(0.03\)
- B \(0.13\)
- C \(0.23\)
- D \(0.33\)
Answer & Solution
Correct Answer
(B) \(0.13\)
Step-by-step Solution
Detailed explanation
\(pH = pK _{ a }+\log \frac{[\text { Salt }]}{[\text { Acid }]}\) \(4=5-\log 1.3+\log \frac{\left[ CH _{3} CH _{2} COO ^{-}\right]}{\left[ CH _{3} CH _{2} COOH \right]}\)…
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