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JEE Advanced · Physics · 26. Dual Nature

An electron in an excited state of Li2+ ion has angular momentum 3h2π . The de Broglie wavelength of the electron in this state is pπα0 (where a0 is the Bohr radius). The value of p is

  1. A 2
  2. B 4
  3. C 6
  4. D 8
Verified Solution

Answer & Solution

Correct Answer

(A) 2

Step-by-step Solution

Detailed explanation

From Bohr's law
mvr=nh2π=3h2π (from eqes.)
n=3
And momentum =mv=3h2πr
Now, radius of nth shell, r=n2za0
r=323.a0 ZLi=3
r=3a0
From De Broglie law
wavelength=hMomentum
λ=hmv=h3h2πr
λ=2πr3=2π3×3a0
λ=2πa0=pπa0
P=2
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