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JEE Advanced · Physics · 13. Thermodynamics

A gas is enclosed in a cylinder with a movable frictionless piston. Its initial thermodynamic state at pressure Pi=105 Pa and volume Vi=10-3 m3 changes to a final state at Pf=132×105 Pa and Vf=8×10-3 m3 in an adiabatic quasi - static process, such that P3V5= constant. Consider another thermodynamic process that brings the system from the same initial state to the same final state in two steps: an isobaric expansion at Pi followed by an isochoric (isovolumetric) process at volumes Vf . The amount of heat supplied to the system in the two step process is approximately

  1. A 112 J
  2. B 294 J
  3. C 588 J
  4. D 813 J
Verified Solution

Answer & Solution

Correct Answer

(C) 588 J

Step-by-step Solution

Detailed explanation

In adiabatic process
P3V5= constant
PV53= constant
γ=53 CV=32R and CP=52R
In another process

Q=nCPT+nCvT
=52 nRTB-TA+32nRTC-TB
Q=52PBVB-PAVA+32 PCVC-PBVB
Putting values
Q=587.5 J 588J
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