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JEE Advanced · Physics · 13. Thermodynamics

A closed container contains a homogeneous mixture of two moles of an ideal monatomic gas γ=53 and one mole of an ideal diatomic gas γ=75. Here, γ is the ratio of the specific heats at constant pressure and constant volume of an ideal gas. The gas mixture does a work of 66 Joule when heated at constant pressure. The change in its internal energy is _____ Joule.

  1. A 118
  2. B 119
  3. C 120
  4. D 121
Verified Solution

Answer & Solution

Correct Answer

(D) 121

Step-by-step Solution

Detailed explanation

Change in internal energy for the mixture can be written as,U=n1Cv1T+n2Cv2T =n1Cv1+n2Cv2T     ...i
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