JEE Advanced · Physics · 21. EMI
A circular insulated copper wire loop is twisted to form two loops of area and as shown in the figure. At the point of crossing the wires remain electrically insulated from each other. The entire loop lies in the plane (of the paper). A uniform magnetic field points into the plane of the paper. At , the loop starts rotating about the common diameter as axis with a constant angular velocity in the magnetic field. Which of the following options is/are correct?
- A The net emf induced due to both the loops is proportional to
- B The amplitude of the maximum net emf induced due to both the loops is equal to the amplitude of the maximum emf induced in the smaller loop alone
- C The rate of change of flux is maximum when plane of loop is perpendicular to the plane of paper
- D The emf induced in the loop is proportional to sum of areas of two loops
Answer & Solution
Correct Answer
(C) The rate of change of flux is maximum when plane of loop is perpendicular to the plane of paper
Step-by-step Solution
Detailed explanation
When a conducting loop rotating in a magnetic field has an angular velocity , the flux through the loop of area at an angle ,
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