JEE Advanced · Mathematics · 19. Determinants
Let \(k\) be a positive real number and let \(\begin{aligned} A & =\left[\begin{array}{ccc}2 k-1 & 2 \sqrt{k} & 2 \sqrt{k} \\ 2 \sqrt{k} & 1 & -2 k \\ -2 \sqrt{k} & 2 k & -1\end{array}\right] \text { and } \\ B & =\left[\begin{array}{ccc}0 & 2 k-1 & \sqrt{k} \\ 1-2 k & 0 & 2 \sqrt{k} \\ -\sqrt{k} & -2 \sqrt{k} & 0\end{array}\right]\end{aligned}\)
If \(\operatorname{det}(\operatorname{adj} A)+\operatorname{det}(\operatorname{adj} B)=10^6\), then \([k]\) is equal to
[Note : adj \(M\) denotes the adjoint of a square matrix \(M\) and \([k]\) denotes the largest integer less than or equal to \(k\) ].
- A 10
- B 15
- C 4
- D 9
Answer & Solution
Correct Answer
(C) 4
Step-by-step Solution
Detailed explanation
\(|A|=(2 k+1)^3,|B|=0\)
But \(\operatorname{det}(\operatorname{adj} A)=\operatorname{det}(\operatorname{adj} B)=10^6\)
\[
\begin{aligned}
& \Rightarrow(2 k+1)^6=10^6 \\
& \Rightarrow k=\frac{9}{2} \Rightarrow[k]=4
\end{aligned}
\]
But \(\operatorname{det}(\operatorname{adj} A)=\operatorname{det}(\operatorname{adj} B)=10^6\)
\[
\begin{aligned}
& \Rightarrow(2 k+1)^6=10^6 \\
& \Rightarrow k=\frac{9}{2} \Rightarrow[k]=4
\end{aligned}
\]
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