JEE Advanced · Mathematics · 6. Binomial Theorem
Let \(a\) and \(b\) be two nonzero real numbers. If the coefficient of \(x^5\) in the expansion of \(\left(a x^2+\frac{70}{27 b x}\right)^4\) is equal to the coefficient of \(x^{-5}\) in the expansion of \(\left(a x-\frac{1}{b x^2}\right)^7\), then the value of \(2 b\) is
- A 3
- B 6
- C 9
- D 12
Answer & Solution
Correct Answer
(A) 3
Step-by-step Solution
Detailed explanation
Given,
The coefficient of in is equal to coefficient of in ,
Now finding the coefficient of in we get,
So,
So,
Now finding the coefficient of in we get,
So,
So,
Now equating the coefficient of we get,
The coefficient of in is equal to coefficient of in ,
Now finding the coefficient of in we get,
So,
So,
Now finding the coefficient of in we get,
So,
So,
Now equating the coefficient of we get,
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