JEE Advanced · Mathematics · 3. Complex Numbers
Let be the vertices of a regular octagon that lie on a circle of radius . Let be a point on the circle and let denote the distance between the points and for . If varies over the circle, then the maximum value of the product , is
- A 500
- B 621
- C 345
- D 512
Answer & Solution
Correct Answer
(D) 512
Step-by-step Solution
Detailed explanation
Given,
vertices of a regular octagon lying on a circle of radius .
Now using the concept of root of unity,
Let any point be,
\(\Rightarrow Z^8=2^8 \times 1 \)
\( \Rightarrow Z^8-2^8=0 \)
\( \Rightarrow Z=2,2 \alpha, 2 \alpha^2, 2 \alpha^3, \ldots, 2 \alpha^7 ;\left\{\text { here } \alpha=e^{i \frac{2 \pi}{8}}\right\} \)
\( \Rightarrow Z^8-2^8=(Z-2)(Z-2 \alpha)\left(Z-2 \alpha^2\right)\)\(\left(Z-2 \alpha^3\right) \ldots\left(Z-2 \alpha^7\right) \)
\( \Rightarrow\left|Z^8-2^8\right|=|Z-2||Z-2 \alpha| \ldots\left|Z-2 \alpha^7\right| \)
\( \text { But }\left|Z^8+\left(-2^8\right)\right| \leq|Z|^8+2^8 \)
\( \Rightarrow|Z-2||Z-2 \alpha| \ldots\left|Z-2 \alpha^7\right| \leq|Z|^8+2^8 \)
\( \leq 2^8+2^8 \)
\( \leq 2^9 \)
\( \Rightarrow \operatorname{Max}\left(P A_1 \cdot P A_2 \ldots P A_8\right)=2^9=512\)
vertices of a regular octagon lying on a circle of radius .
Now using the concept of root of unity,
Let any point be,
\(\Rightarrow Z^8=2^8 \times 1 \)
\( \Rightarrow Z^8-2^8=0 \)
\( \Rightarrow Z=2,2 \alpha, 2 \alpha^2, 2 \alpha^3, \ldots, 2 \alpha^7 ;\left\{\text { here } \alpha=e^{i \frac{2 \pi}{8}}\right\} \)
\( \Rightarrow Z^8-2^8=(Z-2)(Z-2 \alpha)\left(Z-2 \alpha^2\right)\)\(\left(Z-2 \alpha^3\right) \ldots\left(Z-2 \alpha^7\right) \)
\( \Rightarrow\left|Z^8-2^8\right|=|Z-2||Z-2 \alpha| \ldots\left|Z-2 \alpha^7\right| \)
\( \text { But }\left|Z^8+\left(-2^8\right)\right| \leq|Z|^8+2^8 \)
\( \Rightarrow|Z-2||Z-2 \alpha| \ldots\left|Z-2 \alpha^7\right| \leq|Z|^8+2^8 \)
\( \leq 2^8+2^8 \)
\( \leq 2^9 \)
\( \Rightarrow \operatorname{Max}\left(P A_1 \cdot P A_2 \ldots P A_8\right)=2^9=512\)
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