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JEE Advanced · Mathematics · 3. Complex Numbers

Let A1,A2,A3,,A8 be the vertices of a regular octagon that lie on a circle of radius 2. Let P be a point on the circle and let PAi denote the distance between the points P and Ai for i=1,2,,8. If P varies over the circle, then the maximum value of the product PA1·PA2·PA8, is

  1. A 500
  2. B 621
  3. C 345
  4. D 512
Verified Solution

Answer & Solution

Correct Answer

(D) 512

Step-by-step Solution

Detailed explanation

Given,
A1,A2,A3,,A8 vertices of a regular octagon lying on a circle of radius 2.
Now using the concept of nth root of unity,
Let any point P be, Z=(2)(1)1/8
\(\Rightarrow Z^8=2^8 \times 1 \)
\( \Rightarrow Z^8-2^8=0 \)
\( \Rightarrow Z=2,2 \alpha, 2 \alpha^2, 2 \alpha^3, \ldots, 2 \alpha^7 ;\left\{\text { here } \alpha=e^{i \frac{2 \pi}{8}}\right\} \)
\( \Rightarrow Z^8-2^8=(Z-2)(Z-2 \alpha)\left(Z-2 \alpha^2\right)\)\(\left(Z-2 \alpha^3\right) \ldots\left(Z-2 \alpha^7\right) \)
\( \Rightarrow\left|Z^8-2^8\right|=|Z-2||Z-2 \alpha| \ldots\left|Z-2 \alpha^7\right| \)
\( \text { But }\left|Z^8+\left(-2^8\right)\right| \leq|Z|^8+2^8 \)
\( \Rightarrow|Z-2||Z-2 \alpha| \ldots\left|Z-2 \alpha^7\right| \leq|Z|^8+2^8 \)
\( \leq 2^8+2^8 \)
\( \leq 2^9 \)
\( \Rightarrow \operatorname{Max}\left(P A_1 \cdot P A_2 \ldots P A_8\right)=2^9=512\)
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