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JEE Advanced · Mathematics · 31. 3D Geometry

Consider the planes \(3 x-6 y-2 z=15\) and \(2 x+y-2 z=5\).
Statement I The parametric equations of the line of intersection of the given planes are \(x=3+14 t, y=1+2 t\) and \(z=15 t\).
Statement II The vectors \(14 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}+15 \hat{\mathbf{k}}\) is parallel to the line of intersection of the given planes.

  1. A Statement I is true, Statement II is true; Statement II is a correct explanation for Statement I
  2. B Statement I is true, Statement II is true; Statement II is not a correct explanation for Statement I
  3. C Statement I is true, Statement II is false
  4. D Statement I is false, Statement II is true
Verified Solution

Answer & Solution

Correct Answer

(D) Statement I is false, Statement II is true

Step-by-step Solution

Detailed explanation

Given planes are \(3 x-6 y-2 z=15\) and \(2 x+y-2 z=5\)
For \(z=0\), we get \(x=3, y=-1\)
Direction ratios of planes are
\[
< 3-6-2>\text { and } < 2 \quad 1-2>
\]
then the dr's of line of intersection of planes is \(\langle 14215\rangle\) and line is
\[
\begin{aligned}
\frac{x-3}{14} & =\frac{y+1}{2}=\frac{z-0}{15}=\lambda \text { (say) } \\
\Rightarrow \quad x & =14 \lambda+3, y=2 \lambda-1, z=15 \lambda
\end{aligned}
\]
Hence, Statement I is false.
But Statement II is true.
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