JEE Advanced · Chemistry · 21. p Block (G15-18)

The reaction of $Pb {({NO}_{3})}_{2}$ and $NaCl$ in water produces a precipitate that dissolves upon the addition of $HCl$ of appropriate concentration. The dissolution of the precipitate is due to the formation of

A ${PbCl}_{2}$
B ${PbCl}_{4}$
C ${[{PbCl}_{4}]}^{2 -}$
D ${[{PbCl}_{6}]}^{2 -}$

Verified Solution

Answer & Solution

Correct Answer

(C) ${[{PbCl}_{4}]}^{2 -}$

Step-by-step Solution

Detailed explanation

{Pb}^{2 +}

on reaction with

{Cl}^{-}

, produces white precipitate of

{PbCl}_{2}

{Pb}^{2 +} + 2 {Cl}^{-} ⟶ {PbCl}_{2} ↓

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Columns 1, 2 and 3 contain starting materials, reaction conditions and type of reactions respectively.

Column 1	Column 2	Column 3
(I) Toulene	(i) $NaOH$ $ /Br _2$	(P) Condensation
(II) Acetophenone	(ii) $B r_2 / h v$	(Q) Carboxylation
(III) Benzaldehyde	(iii) $\left( CH _3 CO \right)_2$ $O / CH _3$ $COOK$	(R) Substitution
(IV) Phenol	(iv) $NaOH$ $/CO _2$	(S) Haloform

The only CORRECT combination that gives two different carboxylic acids is

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The reaction of PbNO32 and NaCl in water produces a precipitate that dissolves upon the addition of HCl of appropriate concentration. The dissolution of the precipitate is due to the formation of

Step-by-step Solution

The reaction of $Pb {({NO}_{3})}_{2}$ and $NaCl$ in water produces a precipitate that dissolves upon the addition of $HCl$ of appropriate concentration. The dissolution of the precipitate is due to the formation of