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GUJCET · Physics · Electrostatic Potential and Capacitance
Two capacitors \(C_1\) and \(C_2\) are connected in parallel. If a charge \(Q\) is given to the combination, The charge gets shared. Then the ratio of charge on \(C_1\) to charge on \(C_2\) is ________.
- A \(C _1+ C _2\)
- B \(\frac{ C _1}{ C _2}\)
- C \(C _1 C _2\)
- D \(\frac{ C _2}{ C _1}\)
Answer & Solution
Correct Answer
(B) \(\frac{ C _1}{ C _2}\)
Step-by-step Solution
Detailed explanation
(B)
As \(C_1\) and \(C_2\) are connected in parallel, so the potential will be same for both.
\(V_1=V_2\)
\(\therefore \quad \frac{q_1}{ C _1}=\frac{q_2}{ C _2} \quad\left(\because C =\frac{ Q }{ V }\right)\)
\(\therefore \quad \frac{q_1}{q_2}=\frac{ C _1}{ C _2}\)
As \(C_1\) and \(C_2\) are connected in parallel, so the potential will be same for both.
\(V_1=V_2\)
\(\therefore \quad \frac{q_1}{ C _1}=\frac{q_2}{ C _2} \quad\left(\because C =\frac{ Q }{ V }\right)\)
\(\therefore \quad \frac{q_1}{q_2}=\frac{ C _1}{ C _2}\)
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