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GUJCET · Physics · Moving Charges and Magnetism

The ratio of magnetic field at the centre of the ring of radius \(R\) to the point on the axis at a distance \(2 \sqrt{2} R\) from its centre is ___________ .

  1. A \(27: 1\)
  2. B \(81: 1\)
  3. C \(1: 9\)
  4. D \(1: 2 \sqrt{2}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(27: 1\)

Step-by-step Solution

Detailed explanation

\(B_c = \frac{\mu_0 I}{2R}\) \(B_a = \frac{\mu_0 I R^2}{2(R^2 + x^2)^{3/2}}\)