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GUJCET · Physics · Electrostatic Potential and Capacitance
The potential energy of system of two equal negative point charges of \(2 \mu C\) each held 1 m apart in air is __________. \(\left( k =9 \times 10^9\right.\) SI Unit \()\)
- A \(3.6 \times 10^{-3} J\)
- B \(3.6 \times 10^{-2} J\)
- C 36 J
- D 3.6 J
Answer & Solution
Correct Answer
(B) \(3.6 \times 10^{-2} J\)
Step-by-step Solution
Detailed explanation
(B)
\(\begin{aligned} U & =\frac{k q_1 q_2}{r_{12}} \\ \therefore \quad U & =\frac{9 \times 10^9 \times\left(-2 \times 10^{-6}\right)^2}{1} \\ \therefore \quad U & =9 \times 10^9 \times 4 \times 10^{-12} \\ \therefore \quad U & =36 \times 10^{-3} \\ \therefore \quad U & =3.6 \times 10^{-2} J\end{aligned}\)
\(\begin{aligned} U & =\frac{k q_1 q_2}{r_{12}} \\ \therefore \quad U & =\frac{9 \times 10^9 \times\left(-2 \times 10^{-6}\right)^2}{1} \\ \therefore \quad U & =9 \times 10^9 \times 4 \times 10^{-12} \\ \therefore \quad U & =36 \times 10^{-3} \\ \therefore \quad U & =3.6 \times 10^{-2} J\end{aligned}\)
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