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GUJCET · Physics · Nuclei
The energy released by the fission of one uranium atom is 200 MeV . The number of fission per second required to produce 6.4 W power is \(\qquad\) .
- A \(10^{11}\)
- B \(2 \times 10^{11}\)
- C \(10^{10}\)
- D \(2 \times 10^{10}\)
Answer & Solution
Correct Answer
(B) \(2 \times 10^{11}\)
Step-by-step Solution
Detailed explanation
B.\(2 \times 10^{11}\)
Power \(\mathrm{P}=\frac{n \mathrm{E}}{t}\)
\(\therefore n=\frac{\mathrm{P}_{t}}{\mathrm{E}}\)
\(\therefore n=\frac{6.4 \times 1}{200 \times 10^{6} \times 1.6 \times 10^{-19}}\)
\(\therefore n \approx 2 \times 10^{11}\)
Power \(\mathrm{P}=\frac{n \mathrm{E}}{t}\)
\(\therefore n=\frac{\mathrm{P}_{t}}{\mathrm{E}}\)
\(\therefore n=\frac{6.4 \times 1}{200 \times 10^{6} \times 1.6 \times 10^{-19}}\)
\(\therefore n \approx 2 \times 10^{11}\)
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