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GUJCET · Maths · Application of Integrals
Area enclosed by ellipse \(9 x^2+4 y^2=1\) in the first quadrant is _________ .
- A \(6 \pi\)
- B \(\frac{\pi}{6}\)
- C \(\frac{3 \pi}{2}\)
- D \(\frac{\pi}{24}\)
Answer & Solution
Correct Answer
(D) \(\frac{\pi}{24}\)
Step-by-step Solution
Detailed explanation
Equation of ellipse: \( \frac{x^2}{1/9} + \frac{y^2}{1/4} = 1 \) Semi-axes: \( a = 1/3, b = 1/2 \)
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