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GUJCET · Physics · Electrostatic Potential and Capacitance
The electric potential at any point (x, y, z) (all in meters) in space is given by \(V =5 x^2\) volt. The electric field at the point (1,2,3) m is \(\overrightarrow{ E }=\) ________ \(\frac{ N }{ C }\).
- A \(\hat{i}+2 \hat{j}+3 \hat{k}\)
- B \(-20 \hat{j}\)
- C \(-30 \hat{k}\)
- D \(-10 \hat{i}\)
Answer & Solution
Correct Answer
(D) \(-10 \hat{i}\)
Step-by-step Solution
Detailed explanation
(D)
\(\begin{aligned} & E= - \frac{N}{d x} \\ \therefore & E= - \frac{d}{d x}\left(5 x^2\right) \\ \therefore & E= -10 x \\ \therefore & E=-10(1) \\ \therefore & E=-10 i \frac{N}{C}\end{aligned}\)
\(\begin{aligned} & E= - \frac{N}{d x} \\ \therefore & E= - \frac{d}{d x}\left(5 x^2\right) \\ \therefore & E= -10 x \\ \therefore & E=-10(1) \\ \therefore & E=-10 i \frac{N}{C}\end{aligned}\)
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