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GUJCET · Physics · Moving Charges and Magnetism
A horizontal overhead power line carries a current of 90A in east to west direction. What is the magnitude and direction of the magnetic field due to the current 1.5m above the line?
- A \(1.2 \times 10^{-5} \mathrm{~T}\),towards north
- B \(1.2 \pi \times 10^{-5} \mathrm{~T}\), towards north
- C \(1.2 \times 10^{-5} \mathrm{~T}\), towards south
- D \(1.2 \pi \times 10^{-5} \mathrm{~T}\), towards south
Answer & Solution
Correct Answer
(A) \(1.2 \times 10^{-5} \mathrm{~T}\),towards north
Step-by-step Solution
Detailed explanation
\( B = \frac{\mu_0 I}{2 \pi r} \) \( B = \frac{(4 \pi \times 10^{-7}) \times 90}{2 \pi \times 1.5} = 1.2 \times 10^{-5} \mathrm{~T} \)
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