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GUJCET · Physics · Electromagnetic Induction
A conducting coil having 500 turns has crosssectional area \(0.15 m^2\). A magnetic filed of strength 0.2 T linked perpendicular to this area changes to 1.0 T in 0.4 sec . The induced emf produced in the coil will be ________ Volt.
- A 100
- B 15.0
- C 75.0
- D 150.0
Answer & Solution
Correct Answer
(D) 150.0
Step-by-step Solution
Detailed explanation
D
\(\begin{aligned}|\varepsilon| & = N \frac{\Delta \phi}{\Delta t}=\frac{ N \left(\phi_2-\phi_1\right)}{\Delta t} \\ |\varepsilon| & =\frac{ NA \left( B _2- B _1\right)}{\Delta t}(\because \phi= AB ) \\ |\varepsilon| & =\frac{500 \times 0.15 \times(1-0.2)}{0.4} \\ & =150 V\end{aligned}\)
\(\begin{aligned}|\varepsilon| & = N \frac{\Delta \phi}{\Delta t}=\frac{ N \left(\phi_2-\phi_1\right)}{\Delta t} \\ |\varepsilon| & =\frac{ NA \left( B _2- B _1\right)}{\Delta t}(\because \phi= AB ) \\ |\varepsilon| & =\frac{500 \times 0.15 \times(1-0.2)}{0.4} \\ & =150 V\end{aligned}\)
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