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GUJCET · Chemistry · Chemical Kinetics
Time required to decompose \(SO _2 Cl _2\) to half of its initial amount is \(4 0\) minutes. If the decomposition is a first order reaction, what will be the rate constant of the reaction?
- A \(2.88 \times 10^{-4} s^{-1}\)
- B \(2.88 \times 10^{-2} s^{-1}\)
- C \(1.73 \times 10^{-2} s^{-1}\)
- D \(1.73 \times 10^{-4} s^{-1}\)
Answer & Solution
Correct Answer
(A) \(2.88 \times 10^{-4} s^{-1}\)
Step-by-step Solution
Detailed explanation
A
\(\begin{aligned}
\frac{t_1}{2} & =40 min \\
& =40 \times 60 \\
& =2400 Sec\end{aligned}\)
For First order reaction
\(\begin{aligned}
k=\frac{0.693}{t \frac{1}{2}}=\frac{0.693}{2400} & =0.000288 \\
& =2.88 \times 10^{-4} Sec^{-1}\end{aligned}\)
\(\begin{aligned}
\frac{t_1}{2} & =40 min \\
& =40 \times 60 \\
& =2400 Sec\end{aligned}\)
For First order reaction
\(\begin{aligned}
k=\frac{0.693}{t \frac{1}{2}}=\frac{0.693}{2400} & =0.000288 \\
& =2.88 \times 10^{-4} Sec^{-1}\end{aligned}\)
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