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AP EAMCET · PHYSICS · Current Electricity

A battery of emf \(10 \mathrm{~V}\) is connected to a uniform wire \(A B\) of \(1 \mathrm{~m}\) length and having a resistance of \(10 \Omega\) in series with a \(10 \Omega\) resistor as shown in the figure. Two cells of emf \(2 \mathrm{~V}\) and \(3 \mathrm{~V}\) having internal resistance \(2 \Omega\) and \(3 \Omega\), respectively are connected as shown in the figure. If the galvanometer shows null deflection at point \(J\) on the wire, then the distance of point \(J\) from the point \(B\) is.

  1. A 48 cm
  2. B 50 cm
  3. C 52 cm
  4. D 54 cm
Verified Solution

Answer & Solution

Correct Answer

(C) 52 cm

Step-by-step Solution

Detailed explanation

Given \(r=10 \Omega, R=10 \Omega, E=10 \mathrm{~V}\) and \(L=100 \mathrm{~cm}\). Now, voltage drop on the wire, \(E^{\prime}=\frac{E}{(r+R)} \times R\) \( \Rightarrow \quad E^{\prime}=\frac{10}{20} \times 10=5 R \) So, potential gradient on wire,…
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