AP EAMCET · PHYSICS · Alternating Current
When an inductor of inductance \(\frac{6}{\pi} \mathrm{H}\), a capacitor of capacitance \(\frac{50}{\pi} \mu \mathrm{F}\) and resistor of resistance \(R\) are connected in series with an AC supply of rms voltage \(220 \mathrm{~V}\) and frequency \(50 \mathrm{~Hz}\), the rms current through the circuit is \(440 \mathrm{~mA}\). Match the inductive reactance, \(X_L\) the capacitive reactance, \(X_C\) the resistance \(R\) and the impedance \(Z\) of the circuit given in List-I with the corresponding values given in List-II.
\(\begin{array}{llll} \hline & \text { List- I } & & \text { List- II } \\ \hline \text {(A) } & X_L & \text { (i) } & 200 \Omega \\ \hline \text {(B) } & X_C & \text { (ii) } & 300 \Omega \\ \hline \text {(C) } & R & \text { (iii) } & 500 \Omega \\ \hline \text {(D) } & Z & \text { (iv) } & 600 \Omega \\ \hline \end{array}\)
- A \(\begin{array}{cc}\text { A } & \text { B } & \text { C } & \text { D } \\ \text {(iv) } & \text { (ii) } & \text { (i) } & \text { (iii) }\end{array}\)
- B \(\begin{array}{cc}\text { A } & \text { B } & \text { C } & \text { D } \\ \text { (iv) } & \text { (iii) } & \text { (i) } & \text { (ii) } \end{array}\)
- C \(\begin{array}{cc}\text { A } & \text { B } & \text { C } & \text { D } \\ \text { (iv) } & \text { (i) } & \text { (ii) } & \text { (iii) } \end{array}\)
- D \(\begin{array}{cc}\text { A } & \text { B } & \text { C } & \text { D } \\ \text { (i) } & \text { (iv) } & \text { (iii) } & \text { (ii) }\end{array}\)
Answer & Solution
Correct Answer
(C) \(\begin{array}{cc}\text { A } & \text { B } & \text { C } & \text { D } \\ \text { (iv) } & \text { (i) } & \text { (ii) } & \text { (iii) } \end{array}\)
Step-by-step Solution
Detailed explanation
Given, inductance of inductor, \(L=\frac{6}{\pi} \mathrm{H}\), capacitance of capacitor, \(C=\frac{50}{\pi} \mu \mathrm{F}\) supply voltage, \(V_{\text {rms }}=220 \mathrm{~V}\), supply frequency, \(f=50 \mathrm{~Hz}\) and supply current, \(I_{\mathrm{rms}}=440 \mathrm{~mA}\)…
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