AP EAMCET · PHYSICS · Mechanical Properties of Fluids
A cylindrical tank having large diameter is filled with water to a height \(H\). A hole of cross-sectional area \(5 \mathrm{~cm}^2\) in the tank allows water to drain out. If the water drains out at the rate of \(2 \times 10^{-3} \mathrm{~m}^3 \mathrm{~s}^{-1}\), then the value of \(H\) is (acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A \(80 \mathrm{~cm}\)
- B \(120 \mathrm{~cm}\)
- C \(60 \mathrm{~cm}\)
- D \(90 \mathrm{~cm}\)
Answer & Solution
Correct Answer
(A) \(80 \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
The given situation is shown below Velocity of efflux through a hole below depth \(\mathrm{H}\) of fluid, \(v=\sqrt{2 g H}\) Volume flow rate of fluid from hole of area \[ \begin{aligned} & a=V=a v \\ & V=a \sqrt{2 g H} \end{aligned} \] Here…
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