AP EAMCET · PHYSICS · Communication System
A T.V. tower has a height of \(100 \mathrm{~m}\). The average population density around the tower is \(1000 \mathrm{~km}^{-2}\) and radius of the earth is \(6.37 \times 10^6 \mathrm{~m}\). The population covered is
- A \(4 \times 10^6\)
- B \(6 \times 10^4\)
- C \(16 \times 10^4\)
- D \(8 \times 10^6\)
Answer & Solution
Correct Answer
(A) \(4 \times 10^6\)
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