AP EAMCET · PHYSICS · Magnetic Effects of Current
Two long straight parallel conductors \(10 \mathrm{~cm}\) apart, carry equal currents of magnitude \(3 \mathrm{~A}\) in the same direction. Then, the magnetic induction at a point midway between them is
- A \(2 \times 10^{-5} \mathrm{~T}\)
- B \(3 \times 10^{-5} \mathrm{~T}\)
- C zero
- D \(4 \times 10^{-5} \mathrm{~T}\)
Answer & Solution
Correct Answer
(C) zero
Step-by-step Solution
Detailed explanation
At the mid point of two conductors, the magnetic induction. \(B_1=B_2=B\) and \(\vec{B}_1\) is anti \(\|^{\mathrm{r}}\) to \(\vec{B}_2\). Therefore, the net magnetic induction due to two wire at the mid points is \(B_{\mathrm{N}}=B_1-B_2=0\)
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