AP EAMCET · PHYSICS · Electrostatics
Two charges each of charge \(+10 \mu C\) are kept on \(Y\)-axis at \(y=-a\) and \(y=+a\), respectively. Another point charge \(-20 \mu C\) is placed at the origin and given a small displacement \(x(x< < a)\) along \(X\)-axis. The force acting on the point charge is
\(\left(x \text { and } a \text { are in metres, } \frac{1}{4 \pi \varepsilon_0}=9 \times 10^9 \mathrm{~N}-\mathrm{m}^2 \mathrm{C}^{-2}\right)\)
- A \(\frac{3.6 x}{a^2} \mathrm{~N}\)
- B \(\frac{2.4 x^2}{a^2} \mathrm{~N}\)
- C \(\frac{3.6 x}{a^3} \mathrm{~N}\)
- D \(\frac{4.8 x}{a^2} \mathrm{~N}\)
Answer & Solution
Correct Answer
(C) \(\frac{3.6 x}{a^3} \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
If force acting on each charge \(+10 \mu \mathrm{C}\) be \(\mathrm{F}\) and \(\mathrm{x}\) be the displaced position…
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