AP EAMCET · Maths · Trigonometric Equations
In \(\triangle A B C\) if \(x=\tan \left(\frac{B-C}{2}\right) \tan \frac{A}{2}\), \(y=\tan \left(\frac{C-A}{2}\right) \tan \frac{B}{2}\), and \(z=\tan \left(\frac{A-B}{2}\right) \tan \frac{C}{2}\), then \((x+y+z)\) is equal to
- A \(xyz\)
- B \(-xyz\)
- C \(2xyz\)
- D \(\frac {1}{2}xyz\)
Answer & Solution
Correct Answer
(B) \(-xyz\)
Step-by-step Solution
Detailed explanation
In \(\triangle \mathrm{ABC}\), given \(\begin{aligned} & x=\tan \left(\frac{B-C}{2}\right) \tan \frac{A}{2} \\ & y=\tan \left(\frac{C-A}{2}\right) \tan \frac{B}{2} \end{aligned}\) and \(y=\tan \left(\frac{A-B}{2}\right) \tan \frac{C}{2}\) Since,…
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