AP EAMCET · PHYSICS · Gravitation
Two bodies of masses \(4 \mathrm{~m}\) and \(9 \mathrm{~m}\) are separated by a distance ' \(r\) '. The gravitational potential at a point on this line joining them where the gravitational field becomes zero is
- A \(\frac{-25 G m}{r}\)
- B \(\frac{-4 G m}{r}\)
- C \(\frac{-9 G m}{r}\)
- D \(\frac{-13 G m}{r}\)
Answer & Solution
Correct Answer
(A) \(\frac{-25 G m}{r}\)
Step-by-step Solution
Detailed explanation
At the position when the gravitational field is zero. (Distance \(x\) is measured from \(4 \mathrm{~m}\) mass)…
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