AP EAMCET · PHYSICS · Work Power Energy
Two bodies A and B of masses 1.5 kg and 3 kg are moving with velocities \(20 \mathrm{~m} \mathrm{~s}^{-1}\) and \(15 \mathrm{~m} \mathrm{~s}^{-1}\) respectively. If the same retarding force is applied on the two bodies, then the ratio of the distances travelled by the bodies \(A\) and \(B\) before they come to rest is
- A \(1: 1\)
- B \(8: 9\)
- C \(2: 3\)
- D \(3: 8\)
Answer & Solution
Correct Answer
(B) \(8: 9\)
Step-by-step Solution
Detailed explanation
\(d = \frac{mv^2}{2F}\) \(\frac{d_A}{d_B} = \frac{m_A v_A^2}{m_B v_B^2}\) \(\frac{d_A}{d_B} = \frac{1.5 \times (20)^2}{3 \times (15)^2}\) \(\frac{d_A}{d_B} = \frac{1.5 \times 400}{3 \times 225}\) \(\frac{d_A}{d_B} = \frac{600}{675}\) \(\frac{d_A}{d_B} = \frac{8}{9}\)
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