AP EAMCET · PHYSICS · Oscillations
Time period of a simple pendulum of length ' \(L\) ' is \(T_1\). Time period of a uniform rod of same length ' \(L\) ' suspended from one end and oscillating in a vertical plane is \(T_2\). Amplitude of oscillation is small in both the cases. Then \(\frac{T_1}{T_2}\) is
- A \(\sqrt{\frac{2}{3}}\)
- B \(\sqrt{\frac{3}{2}}\)
- C \(\sqrt{\frac{4}{3}}\)
- D 1
Answer & Solution
Correct Answer
(B) \(\sqrt{\frac{3}{2}}\)
Step-by-step Solution
Detailed explanation
Length of pendulum \(=L\) Time period of simple pendulum \[ T_1=2 \pi \sqrt{\frac{L}{g}} \] Length of \(\operatorname{rod}=L\) Time period of rod;…
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