AP EAMCET · PHYSICS · Mechanical Properties of Solids
\(A 3 \mathrm{~m}\) long steel wire is stretched to increase its length by \(0.3 \mathrm{~cm}\). Poisson's ratio for steel is 0.26 . The lateral strain produced in the wire is
- A \(0.26 \times 10^{-4}\)
- B \(0.26 \times 10^{-2}\)
- C \(0.26 \times 10^{-3}\)
- D \(0.26 \times 10^{-1}\)
Answer & Solution
Correct Answer
(C) \(0.26 \times 10^{-3}\)
Step-by-step Solution
Detailed explanation
Length of steel wire, \(l=3 \mathrm{~m}\) Increased length, \(\Delta l=0.3 \mathrm{~cm}=3 \times 10^{-3} \mathrm{~m}\) Poisson's ratio \(=0.26\) \(\Rightarrow \quad \frac{\text { Lateral strain }}{\text { Longitudinal strain }}=0.26\) \(\Rightarrow\) Lateral strain…
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