AP EAMCET · PHYSICS · Ray Optics
The voltage applied to an electron microscope to produce electrons of wavelength \(0.50 Å\) is
- A \(602 \mathrm{~V}\)
- B \(50 \mathrm{~V}\)
- C \(138 \mathrm{~V}\)
- D \(812 \mathrm{~V}\)
Answer & Solution
Correct Answer
(A) \(602 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
Given, wavelength of electron, \(\lambda=0.5 Å\) By using de-Broglie wavelength, \[ \lambda=\frac{h}{\sqrt{2 m e V}} \] where, \(h\) is Planck's constant \(=6.63 \times 10^{-34} \mathrm{~J}-\mathrm{s}\), \(m\) is mass of electron, \(e\) is charge of electron and \(V\) is applied…
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