AP EAMCET · PHYSICS · Ray Optics
A light ray incidents normally on one surface of an equilateral prism. The angle of deviation of the light ray is (refractive index of the material of the prism \(=\sqrt{2}\) )
- A \(60^{\circ}\)
- B \(30^{\circ}\)
- C \(0^{\circ}\)
- D \(120^{\circ}\)
Answer & Solution
Correct Answer
(A) \(60^{\circ}\)
Step-by-step Solution
Detailed explanation
Given, \(i=0^{\circ}\) So, \( \begin{aligned} \frac{\sin i}{\sin r_1} & =\sqrt{2} \\ \frac{\sin 0^{\circ}}{\sin r_1} & =\sqrt{2} \\ \sin r_1 & =0 \text { or } r_1=0 \end{aligned} \) Now, \(\frac{\sin r_2}{\sin e}=\frac{1}{\mu}\) \( \Rightarrow \quad \sin e=\sqrt{2} \sin r_2 \)…
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