AP EAMCET · PHYSICS · Current Electricity
The value of shunt resistance, that allows only \(10 \%\) of main current through the galvanometer of resistance \(99 \Omega\) is
- A \(9 \Omega\)
- B \(4 \Omega\)
- C \(2 \Omega\)
- D \(11 \Omega\)
Answer & Solution
Correct Answer
(D) \(11 \Omega\)
Step-by-step Solution
Detailed explanation
\(\mathrm{G}=99 \Omega, \mathrm{I}_{\mathrm{g}}=\frac{1}{10}\) \(\therefore \quad\) From figure, \(\mathrm{I}_{\mathrm{g}} \cdot \mathrm{G}=\left(\mathrm{I}-\mathrm{I}_{\mathrm{g}}\right) \mathrm{S}\)…
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