AP EAMCET · PHYSICS · Electromagnetic Induction
The self-inductance of a coil is \(50 \mathrm{mH}\). When a current of 1 A passing through the coil, reduces to zero at a steady rate in \(0.1 \mathrm{~s}\), then find the self-induced emf.
- A \(5 \mathrm{~V}\)
- B \(0.05 \mathrm{~V}\)
- C \(50 \mathrm{~V}\)
- D \(0.5 \mathrm{~V}\)
Answer & Solution
Correct Answer
(D) \(0.5 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
Given, self inductance, \(L=50 \mathrm{mH}\) Change in current, \(I=1 \mathrm{~A}\) Time, \(t=0.1 \mathrm{~s}\) As, \(\quad \operatorname{emf}(\varepsilon)=L \frac{d i}{d t}\) \(\Rightarrow \quad \varepsilon=50 \times 10^{-3} \times \frac{1}{0.1}=0.5 \mathrm{~V}\)
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