AP EAMCET · PHYSICS · Work Power Energy
A motor can pump 7560 kg of water per hour from a well of depth 100 m. If the efficiency of the pump is \(70 \%\), then power of the pump is (Acceleration due to gravity \(=10 \mathrm{~m} \mathrm{~s}^{-2}\) )
- A 4 kW
- B 6 kW
- C 3 kW
- D 7 kW
Answer & Solution
Correct Answer
(C) 3 kW
Step-by-step Solution
Detailed explanation
\(P_{out} = \frac{mgh}{t} = \frac{7560 \times 10 \times 100}{3600 \text{ s}}\) \(P_{out} = 2100 \text{ W}\) \(P_{in} = \frac{P_{out}}{\eta} = \frac{2100 \text{ W}}{0.70}\) \(P_{in} = 3000 \text{ W} = 3 \text{ kW}\)
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