AP EAMCET · Maths · Differentiation
If \(\sqrt{1-x^6}+\sqrt{1-y^6}=a\left(x^3-y^3\right)\), then \(y^2 \frac{d y}{d x}=\)
- A \(\sqrt{\frac{1-y^6}{1-x^6}}\)
- B \(x \sqrt{\frac{1-y^6}{1-x^6}}\)
- C \(x^2 \sqrt{\frac{1-y^6}{1-x^6}}\)
- D \(\frac{1}{x^2} \sqrt{\frac{1-y^6}{1-x^6}}\)
Answer & Solution
Correct Answer
(C) \(x^2 \sqrt{\frac{1-y^6}{1-x^6}}\)
Step-by-step Solution
Detailed explanation
Given equation is \(\begin{aligned} & \sqrt{1-x^6}+\sqrt{1-y^6}=a\left(x^3-y^3\right) \\ \Rightarrow \quad & \frac{\sqrt{1-x^6}+\sqrt{1-y^6}}{x^3-y^3}=a \end{aligned}\) On differentiating both sides w.r.t., \(x\), we get…
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