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AP EAMCET · Maths · Differentiation

If \(\sqrt{1-x^6}+\sqrt{1-y^6}=a\left(x^3-y^3\right)\), then \(y^2 \frac{d y}{d x}=\)

  1. A \(\sqrt{\frac{1-y^6}{1-x^6}}\)
  2. B \(x \sqrt{\frac{1-y^6}{1-x^6}}\)
  3. C \(x^2 \sqrt{\frac{1-y^6}{1-x^6}}\)
  4. D \(\frac{1}{x^2} \sqrt{\frac{1-y^6}{1-x^6}}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(x^2 \sqrt{\frac{1-y^6}{1-x^6}}\)

Step-by-step Solution

Detailed explanation

Given equation is \(\begin{aligned} & \sqrt{1-x^6}+\sqrt{1-y^6}=a\left(x^3-y^3\right) \\ \Rightarrow \quad & \frac{\sqrt{1-x^6}+\sqrt{1-y^6}}{x^3-y^3}=a \end{aligned}\) On differentiating both sides w.r.t., \(x\), we get…
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