AP EAMCET · PHYSICS · Dual Nature of Matter
A transmitter of power 10 kW emits radio waves of wavelength 500 m . The number of photons emitted per second by the transmitter is of the order of
- A \(10^{37}\)
- B \(10^{31}\)
- C \(10^{25}\)
- D \(10^{43}\)
Answer & Solution
Correct Answer
(B) \(10^{31}\)
Step-by-step Solution
Detailed explanation
Power, \(P=\frac{n h c}{\lambda t}\) \(\therefore \quad\) Number of photons emitted per second,…
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