AP EAMCET · PHYSICS · Communication System
The maximum amplitude of an amplitude modulated wave is \(16 \mathrm{~V}\), while the minimum amplitude is \(4 \mathrm{~V}\). The modulation index is
- A \(0.4\)
- B \(0.5\)
- C \(0.6\)
- D \(4\)
Answer & Solution
Correct Answer
(C) \(0.6\)
Step-by-step Solution
Detailed explanation
We have, \(m=\frac{A_m}{A_c}=\frac{E_{\max }-E_{\min }}{E_{\max }+E_{\min }}\) Here, \(E_{\max }=16 \mathrm{~V}\) and \(E_{\min }=4 \mathrm{~V}\) \(\begin{aligned} & \Rightarrow \quad m=\frac{16-4}{16+4} \\ & =\frac{12}{20}=\frac{3}{5}=0.6 \end{aligned}\)
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