AP EAMCET · PHYSICS · Magnetic Effects of Current
The magnitude of magnetic field at \(O\) due to a current carrying loop as shown in the figure is, where \(O\) is the centre of two circular portions with radii \(1 \mathrm{~cm}\) and \(2 \mathrm{~cm}\) respectively is
(Take, the value of current \(I=\frac{1.2}{\pi} \mathrm{A}\) )

- A 10 ñT
- B \(0.1 \mathrm{nT}\)
- C \(100 \mu \mathrm{T}\)
- D \(1 \mathrm\mu{T}\)
Answer & Solution
Correct Answer
(D) \(1 \mathrm\mu{T}\)
Step-by-step Solution
Detailed explanation
Wire lengths \(a b\) and \(c d\) does not produces any field at \(O\) as this point lies an axis of wires. Arc \(b c\) produces an inward \(\otimes\) magnetic field given by \(B_1=\frac{\mu_0 I}{2 R_1} \times \frac{\theta}{360^{\circ}}\)…
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