AP EAMCET · PHYSICS · Magnetic Effects of Current
The magnetic field due to current carrying circular loop of radius \(6 \mathrm{~cm}\) at a point on the axis at a distance of \(8 \mathrm{~cm}\) from centre is \(27 \mu \mathrm{T}\). The magnetic field at the centre of the current carrying loop is.
- A \(75 \mu \mathrm{T}\)
- B \(125 \mu \mathrm{T}\)
- C \(150 \mu \mathrm{T}\)
- D \(250 \mu \mathrm{T}\)
Answer & Solution
Correct Answer
(B) \(125 \mu \mathrm{T}\)
Step-by-step Solution
Detailed explanation
( Magnetic field due to a current carrying coil of radius \(R\) on its axis at a distance \(x\) from its centre is \[ B_{\text {axis }}=\frac{\mu_0 N I R^2}{2\left(x^2+R^2\right)^{\frac{3}{2}}} \] Here, \(x=8 \mathrm{~cm},=8 \times 10^{-2} \mathrm{~m}\)…
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