AP EAMCET · PHYSICS · Oscillations
The equation of motion of a particle executing simple harmonic motion is \(4 \frac{\mathrm{d}^2 \mathrm{y}}{\mathrm{dt}^2}+\pi^2 \mathrm{y}=0\) where \(y\) is in metres and \(t\) is in seconds. The time period of oscillation of the particle is
- A \(1 \mathrm{~s}\)
- B \(2 \mathrm{~s}\)
- C \(3 \mathrm{~s}\)
- D \(4 \mathrm{~s}\)
Answer & Solution
Correct Answer
(D) \(4 \mathrm{~s}\)
Step-by-step Solution
Detailed explanation
Equation of motion: \[ \begin{aligned} & 4 \frac{d^2 y}{d t^2}+\pi^2 y=0 \\ & \frac{d^2 y}{d t^2}+\frac{\pi^2}{4} y=0 \end{aligned} \] General equation of motion is \[ \frac{d^2 y}{d t^2}+\omega^2 y=0 \] On compairing, \(\omega^2=\frac{\pi^2}{2^2}\) \[ \omega=\frac{\pi}{2} \]…
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